tag:blogger.com,1999:blog-6915942954402781501.post73135432649448012..comments2020-05-09T14:38:51.469+01:00Comments on Ian Gent's Blog: Get 55, or any other number, with three 4s.Ian Genthttp://www.blogger.com/profile/14390523974279353420noreply@blogger.comBlogger7125tag:blogger.com,1999:blog-6915942954402781501.post-16856716921163874102009-11-18T15:50:21.025+00:002009-11-18T15:50:21.025+00:00You must have been able to use a square root becau...You must have been able to use a square root because the official answer used one! <br /><br />The official answer is here<br /><br />http://www.cartalk.com/content/puzzler/transcripts/200945/answer.html<br /><br />Though as I read it now it has a typo in it, the last 5 in the equation should obviously be a 4.Ian Genthttps://www.blogger.com/profile/14390523974279353420noreply@blogger.comtag:blogger.com,1999:blog-6915942954402781501.post-92065637210037596422009-11-16T20:10:06.154+00:002009-11-16T20:10:06.154+00:00I thought that you couldn't use the square roo...I thought that you couldn't use the square root int he puzzler because with a square root, it was impled that there was a 2 there.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-6915942954402781501.post-76630048717516253622009-11-10T10:09:43.039+00:002009-11-10T10:09:43.039+00:00Joe, as you say the number has to be embedded some...Joe, as you say the number has to be embedded somehow, but then it would be supercool to embed it in binary or something! <br /><br />Graeme, just to be fair remember I got the idea from somewhere else, which I can't remember now.<br /><br />And I like the zero 4s solution.Ian Genthttps://www.blogger.com/profile/14390523974279353420noreply@blogger.comtag:blogger.com,1999:blog-6915942954402781501.post-69222675662783923832009-11-09T21:43:24.165+00:002009-11-09T21:43:24.165+00:00Very cool idea, thanks for writing it up.
(Graem...Very cool idea, thanks for writing it up. <br /><br />(Graeme)Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-6915942954402781501.post-8725253262596158452009-11-09T06:12:16.750+00:002009-11-09T06:12:16.750+00:00Actually, after thinking a few more minutes, of co...Actually, after thinking a few more minutes, of course the number has to be embedded. Anyway, a cool problem and analysis.<br />Joe C.Joehttp://www.cs.ualberta.ca/~joe/noreply@blogger.comtag:blogger.com,1999:blog-6915942954402781501.post-65847293649214285152009-11-08T20:48:52.985+00:002009-11-08T20:48:52.985+00:00Oops, in the previous {,} should have been <>...Oops, in the previous {,} should have been <> (vector not set).<br />Or something like the set of nested sets on empty e.g. |{ {}, {{}}, ... {{{{...}}}}} }| if you object to x's.Joseph Culbersonhttp://www.cs.ualberta.ca/~joe/noreply@blogger.comtag:blogger.com,1999:blog-6915942954402781501.post-48737485288624927262009-11-08T20:43:16.877+00:002009-11-08T20:43:16.877+00:00if you use n (or n+1) sqrt signs, isn't that k...if you use n (or n+1) sqrt signs, isn't that kind of cheating since it is effectively embedding unary n in the answer?<br />Consider for example, I could get any n with zero 4's if I did |{x,....,x}| with n x's<br /><br />Joe C.Joseph CUlbersonhttp://www.cs.ualberta.ca/~joe/noreply@blogger.com